Let equation of required plane is a(x−2)+b(y+1)+c(z−3)=0 Now, the plane is perpendicular to ‌3x−2y+z=8‌ and ‌x+y+z=6 ‌|
∧
i
∧
j
∧
k
3
−2
1
1
1
1
|=
∧
i
(−3)−
∧
j
(2)+k(5) ∵a,b and c are −3,−2 and 5 ‌−3(x−2)−2(y+1)+5(z−3)=0 ⇒−3x−2y+5z+6−2−15=0 ⇒−3x−2y+5z−11=0 ⇒−3x−2y+5z=11 ⇒−‌