Using Nernst equation, E‌cell ‌‌=E‌cell ‌∘−‌
0.06
n
‌log[‌
Zn2+
Ni2+
] E‌cell ‌∘‌=E‌Cathode ‌∘−E‌Anode ‌∘ ‌=ENi2+∕Ni∘−EZn2+∕Zn∘ ‌=(−0.25V)−(−0.76V)=0.51V Substituting all the given values E‌cell ‌‌=0.51−‌