Number of turns, N=1200 Area of cross-section, A=5cm2=5×10−4m2 Magnetic moment, M=1.2JT−1 We are asked to find the current I. Step 1: Formula for magnetic moment of a solenoid A solenoid with N turns, cross-sectional area A, and current I has a magnetic moment: M=NIA Step 2: Substitute given values 1.2=1200×I×(5×10−4) Step 3: Simplify ‌1.2=1200×5×10−4×I ‌1.2=(0.6)×I Step 4: Solve for I I=‌