Temperature of an ideal gas increased by =20°C i.e. T2 Initial temperature of gas, T1=0°C Number of moles, n=2 Formula of work done, W=−nR(T2−T1) W=−2R(20−0) W=−40R But work involved in the process, W=+ve W=40R Here, R= Rate constant i.e. 8.314JK−1mol−1 W=40×8.314=332.56JK−1mol−1