Given, applied force, F=40N Horizontal component of force, Fx=20√3 and θ be the angle of force from horizontal X-axis. According to given diagram, The component of F along X-axis will be
Fx=Fcosθ ⇒20√3=40cosθ ⇒
√3
2
=cosθ ∴θ=cos−1(
√3
2
)=30° And the component of F along Y-axis Fy=Fsinθ =Fsin30° =40×
