At infinite dilution, the molar conductivity of an electrolyte can be represented as the sum individual contribution of its cations and anions. λ°m(NH3)→λ°∞(H+)+λ°‌∞(NH2−) λ°m(NH3)=λ°∞(NH2−)+λ°−(H+)+λ°∞ KBr−λ°‌KBr =λ°‌∞(KNH2)+λ°‌∞(HBr)−λ°∞(KBr) =90.48+420.6−120.5 =390.5‌S‌cm2‌mol−1.