If \left(\begin{array}{c}\alpha \ \beta \ \gamma)\end{array}=\left(\begin{array}{cc}\cos heta & - \sin \\theta & 0 \ \sin \\theta & \cos heta & 0 \ 0 & 0 & 1)\end{array}\left(\begin{array}{c}x \ y \ z)\end{array}, then \frac{x^2+y^2+z^2}{\gamma}=

Question

If \left(\begin{array}{c}\alpha \ \beta \ \gamma)\end{array}=\left(\begin{array}{cc}\cos 	heta & - \sin \\theta & 0 \ \sin \\theta & \cos 	heta & 0 \ 0 & 0 & 1)\end{array}\left(\begin{array}{c}x \ y \ z)\end{array}, then \frac{x^2+y^2+z^2}{\gamma}=

Examsnet · Accepted Answer

Correct Answer is : ‌α2+β2+γ2z

cos‌θ	−sin‌θ	0
sin‌θ	cos‌θ	0
0	0	1

AP EAPCET 18th May 2023 Shift 1 Solved Paper