To solve this problem, let's use the relationship for the inverse hyperbolic cosine function: cosh−1x=log(x+√x2−1) Applying this to cosh−12, we get: cosh−12=log(2+√22−1) Simplifying under the square root: √22−1=√4−1=√3 So, the expression becomes: cosh−12=log(2+√3)