To determine the concentration of a
CaCO3 solution in molarity (
mol∕L ), given its concentration is 1000 ppm , we proceed as follows:
Mass of
CaCO3 in 1 Liter:
Since 1000 ppm means 1000 mg of
CaCO3 per liter, it converts to grams as:
‌=1gCalculation of Moles:
The molar mass of
CaCO3 is calculated using the atomic masses:
Ca=40‌ u ‌,C=12‌ u, ‌O=16‌ u. ‌Therefore, the molar mass of
CaCO3=40+12+(16×3)=100g∕mol.
Now, calculate the number of moles (
n ):
n=‌| ‌ Mass of ‌‌‌CaCO3 |
| ‌ Molar mass ‌ |
=‌=0.01molDetermine Molarity:
The molarity (concentration in
mol∕L ) is given by:
‌ Molarity ‌=‌| ‌ Number of moles ‌ |
| ‌ Volume of solution in ‌L |
=‌=0.01mol∕L=10−2mol∕LThus, the concentration of the
CaCO3 solution is
10−2mol∕L.