PQ+PR=QR ⇒ QPR is a straight line. Slope of PQ= Slope of QR
y−4
x−3
=
2−4
1−3
⇒
y−4
x−3
=1 ⇒ y−4=x−3 y=x+1 Substitute value of y in equation 2x−y−1=0 2x−(x+1)−1=0 ⇒ 2x−x−1−1=0 x=2 and y=3 ∴ Coordinates of P is (2,3).