Wires are located at position A and B OA‌=OB=√12+12=√2‌cm ‌=√2×10−2m Magnitude of net magnetic field due to both wire having current 1A is given as
|B|‌=√[‌
µ0I
2Ï€(OA)
]2+[‌
µ0I
2Ï€(OB)
]2 ‌=√(‌
µ0×1
2π√2
)2+(‌
µ0×1
2π√2
)2=‌
µ0
2√2π
√2=‌
µ0
2Ï€
⇒|B|=‌
µ0
2Ï€
......(i) Magnitude of magnetic field due to individual wire OA, ‌B0=‌