‌dx ‌⇒log(y−4)=log(x−3)+log‌C ‌⇒y−4=C(x−3)⇒y=C(x−3)+4 The curve passes through (4,3) ‌3=C(4−3)+4 ⇒‌‌C‌=−1 ⇒‌‌y‌=3−x+4 ⇒‌‌=7−x Substitute y=x inequation y=7−x ‌x=7−x ⇒‌‌2x=7 ⇒‌‌x‌=7∕2 The intersecting point of curve and line is (‌