√3x±(y−2)=0 The intersection point of 2 given lines is (0,2). y−2=±√3x ⇒y=±√3x+2 is a line at a distance of 5 units from (0,2) ‌⇒‌‌√(x−0)2+(y−2)2=5 ‌⇒‌‌x2+(y−2)2=25⇒x2+3x2=25 ‌⇒‌‌x2=25∕4 ‌⇒‌‌x=±‌
5
2
‌ and ‌y=2+‌
5√3
2
Foot of the perpendicular of P on Y-axis is (0,2+‌