CH3COOC2H5+H2O→CH3COOH+C2H5OH Rate =[H2O][CH3COOC2H5] Given, initial [H2O]=2M initial [CH3COOC2H5]=0.001M, Value of K= ?, If 99% ethyl acetate hydrolyse in 10s. As the initial concentrations of ethyl acetate and H2O vary widely. ∴ The reaction might be pseudo Ist order k=
2.303
t
log
A0
A
As 99% is hydrolysed in 10s. So, [A] at 10. s will be 1%, i.e.
