Let x1 and x2 are roots of equation x2+2x−a2=0 and y1 and y2 are roots of equation y2+4b−b2=(x−x1)(x−x2)=0 and y2+4b−b2→y1,y2=(y−y1)(y−y2) (roots of equation) Let A(x1,y1) and B(x2,y2). Now, the equation of circle with diameter AB is given by