When two short magnets of equal dipole moments M are fastened perpendicularly at their centres. Then their resultant dipole moment is given as
M′‌=√M12+M22+2M1M2‌cos‌θ ‌=√M2+M2+2MM‌cos‌90∘ ⇒M′‌=M√2....(i) The magnitude of the magnetic field at a distance d from the centre on the bisector i.e at a distance d on the axial position of dipole, B‌=‌