(b) Mass of cricket ball, m=50g=0.05‌kg Initial velocity of ball, u=50cms−1=0.5ms−1 time, t=0.5s If a be the retardation applied on the cricket ball, then by using v‌=u−at ⇒‌‌0‌=0.5−a×0.5⇒a=‌
0.5
0.5
‌=1m∕s2 Force applied, F‌=‌ mass ‌×‌ acceleration ‌ ‌=0.05×1=0.05N