In=∫cotnxdxI6+I4=∫cot6xdx+∫cot4xdx=∫cot4x(cot2x+1)dx=−∫cot4x⋅(−csc2x)dx=−∫(cotx)4⋅(−csc2x)dx=−5(cotx)5∴ Assertion is true.∫cotnxdx=∫cotn−2x⋅cot2xdx=∫cotn−2x⋅(csc2x−1)dx=∫cotn−2x⋅csc2x⋅dx−∫cotn−2xdx=−∫(cotx)n−2x⋅(−csc2x)dx−∫cotn−2xdx=−n−1(cotx)n−1−∫cotn−2xdx∴ Reason is false.