The angles of △ABC are in ratio 1:2:3. Let A=θ,B=2θ,C=3θ ∵‌A+B+C=180∘ ⇒θ+2θ+3θ=180∘ ⇒‌‌6θ=180∘ ⇒θ=30∘ ∴‌A=30∘,B=60∘‌ and ‌C=90∘ ∵‌‌
a
sin‌A
=‌
b
sin‌B
=‌
c
sin‌C
=k ‌a=ksin‌A,b=ksin‌B‌ and ‌c=ksin‌c ‌a:b:c=ksin‌30∘:ksin‌60∘:ksin‌90∘ ‌‌=‌