Write the force equation for both the blocks. mg‌cos‌30°−T=ma T=m(g‌cos‌30°−a) …… (I) T−mg‌cos‌60°=ma …… (II) From equation (I) and (II), we get ma=m(g‌cos‌30°−a)−mg‌cos‌60° a=
(√3−1)
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g The expression of the magnitude of the acceleration at centre of mass is, acm=|