For vessel A,
The reaction of hydrogen peroxide is shown below,
2H2O2→2H2O+O2 The
10mL O2 is obtained by,
w=| 2‌mol‌of‌H2‌O2×VH2O2 |
| Vat‌NTP |
Substitute the value in above we get,
w==0.03gH2O2 For vessel B,
The solution of 30 mL
O2 is obtained by,
w=| 2‌mol‌of‌H2‌O2×VH2O2 |
| Vat‌NTP |
Substitute the value in above we get,
w==0.09gH2O2 For vessel B,
The molarity is give as,
M= Here, the number of moles of
H2O2 is
n H2 O2 and the volumeoff the solution is
Vsol Substitute the value in above expression.
2= x=17g Thus, the order of weight of
H2O2 in vessel is
C>B>A.