The number of nucleus in 100gm of 92U235 is calculated as, N=
100
M
×NA N=
100
235
×(6.022×1023) N=2.56×1023 nucleus The energy released in the fission of one nucleus is, E′0=E0 E′0=1.88×106×1.6×10−19J E′0=300.8×10−13J The energy released in N nucleus fission is calculated as, E=E′0N E=300.8×10−13×2.56×1023 E=7.71×1012J