where, T1= and temperature of force T2= temperature of sink
∴‌
1
3
=1−‌
T2
T1
⇒‌
T2
T1
=1−‌
1
3
⇒‌
T2
T1
=‌
2
3
....(i)
When temperature of sink is reduced by 40%, then its new temperature, T2′=T2−40% of T2 =T2−0.4T2 ⇒T2′=0.6T2 Now efficiency of Carnot's engine