=102As−1 Induced emf across inductor coil, e‌‌=L‌
dI
dt
=5×10−3×102 ⇒‌‌e‌‌=0.5V Applying Kirchhoff's voltage law between point A and B. ‌VAB+2×10−12−0.5‌‌=0 ⇒‌VAB+20−12.5‌‌=0 ⇒‌VAB+7.5‌‌=0 ⇒‌VAB‌‌=−7.5V