Consider the equation of the hyperbola be
‌−‌=1 It is given that the centre of the hyperbola is (0,0) and its
transverse axis is along x-axis and its length is 12
2a=12 a=6 Substitute this value in equation of hyperbola.
‌−‌=1 The above equation is passes through point (8,2)
‌−‌=1 ‌−‌=1 After simplification,
b=‌ The equation of hyperbola becomes,
‌−‌=1 ‌−‌=1 The eccentricity of hyperbola is,
e=√1+‌ e=√1+‌ e=√‌ e=‌