The value of T is calculated as, T‌‌=√(∆t1)(∆t2) ‌‌=√(2.00)(4.00) ‌‌=2.828427s The round off value of T, so T=2.83s The expression for the relative error of the product is, ±‌
∆T
T
=±(‌
1
2
‌
∆t1
t1
+‌
1
2
‌
∆t2
t2
) Substitute the given values in the above equation. ∆T‌‌=±(‌
1
2
‌
∆t1
t1
+‌
1
2
‌
∆t2
t2
)T ‌‌=±(‌
1
2
‌
0.02
2.00
+‌
1
2
‌
0.02
4.00
)×2.8284 ‌‌=0.02121s The round off value of ∆T, so ∆T=0.02s ‌ Thus, ‌T=(2.83+0.02)s