Factor (b−a) from the first and third columns:D=(b−a)2bacb−ca−bc−acba.In the remaining determinant, the second column equals the first column minus the third column:bac−cba=b−ca−bc−a.Thus the columns of the remaining determinant are linearly dependent, so its determinant is 0.Therefore D=(b−a)2⋅0=0.Hence the correct option is 0 (option C).