Given polar equation of linesin‌θ−cos‌θ=1∕r ......(i) and point (2,π∕6) Let x=r‌cos‌θ=2.cos‌π∕6=√3 and y=r‌sin‌θ=2.sin‌π∕6=1 The cartesian point is (√3,1). Now, we change the polar of line into cartesian form i.e., r‌sin‌θ−r‌cos‌θ=1 ⇒ y−x=1 .......(ii) Equation of perpendicular line to Eq. (ii) is y+x=λ .......(iii) which passes through (√3,1) λ=√3+1 From Eq. (iii), we get x+y=√3+1 Now, we convert this into polar form r‌cos‌θ+r‌sin‌θ=√3+1 ⇒ sin‌θ+cos‌θ=