The equation of perpendicular bisector of the line joining the points A(−2,−1) and B(6,−1) is, x=2 The equation of perpendicular bisector of the line joining the points B(6,−1) and C(2,5) is, y−2=‌‌
4
6
(x−4) 2x−3y=2 The point of intersection of perpendicular bisector of the circumcentre of triangle‌A‌B‌C. C(2,‌‌
2
3
) Thus, the required quadratic equation is, x2−(2+‌‌