Hybridisation state of Be in BeF2 is sp. F→Be−F H=‌
1
2
(V+M−C+A) =‌
1
2
(2+2−0+0)=2(sp) where, V= number of valence electrons of Be=2 H= number of monovalent F atom =2 C= number of cationic charge =0 A= number of anionic charge =0 So, the hybridisation of Be in BeF2 molecule is sp.
