Dimensional formula of work, [W]=[F]×[s] =[MLT−2][L]=[ML2T−2] Similarly, dimensional formulae of Angular momentum [L]=[m][v][r]=[M][LT−1][L] =[ML2T−1] Torque [τ]=[F]×[r] =[MLT−2][L]=[ML2T−2] Potential energy [U]=[m][g][h] =[M][LT−2][L] =[ML2T−2] Linear momentum [p]=[m][v]=[M][LT−1] =[MLT−1] Kinetic energy [K]=‌
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[m][v2] =[M][LT−1]2=[ML2T−2] Velocity [v]=[LT−1] Clearly, dimensional formulae of work and torque are same, hence option (b) is correct.