Magnetic moment is given by µ=√n(n+2) Here, n = number of unpaired electrons ⇒2.83=√n(n+2) ⇒ (2.83)2=n(n+2) ⇒ 8.00=n2+2n ⇒ n2+2n−8=0 ⇒ n2+4n−2n−8=0 ⇒ (n+4)(n−2)=0 n−2[∵m≠−4] Among the given ions
Hence, Ni2+ possesses a magnetic moment of 2.83BM.
