A current loop A\;B\;C\;D is held fixed on the plane of the paper as shown in the figure. The arcs B\;C (radius =b ) and D\;A (radius =a ) of the loop are joined by two straight wires A\;B and C\;D. A steady current I is flowing in the loop. Angle made by A\;B and C\;D at the origin O is 30^{}. Another straight thin wire steady current I₁ flowing out of the plane of the paper is kept at the origin. The magnitude of the magnetic field (B) due to the loop A\;B\;C\;D at the origin (O) is : [AIEEE 2009]

Question

Examsnet · Accepted Answer

Correct Answer is : μ0I(b−a)24ab\; ₀ I (b - a)/24 a b24abμ0​I(b−a)​

AIEEE 2009 Solved Paper