Given S={(x,y):y=x+1 and 0<x<2} As x≠x+1 for any x∈(0,2)⇒(x,x)∉S ∴S is not reflexive. Hence S in not an equivalence relation. Also T={x,y):x−y is an integer } as x−x=0 is an integer ∀x∈R ∴T is reflexive. If x−y is an integer then y−x is also an integer ∴T is symmetric If x−y is an integer and y−z is an integer then (x−y)+(y−z)=x−z is also an integer. ∴T is transitive Hence T is an equivalence relation