(r+2)th term =‌2nCr+1(x)r And coefficient of (r+2)th=‌2nCr+1 3r‌th ‌ term =‌2nC3r−1(x)3r−1 And coefficient of 3r‌th ‌ term =‌2nC3r−1 And coefficient of 3r‌th ‌ term =‌2nC3r−1 According to the question, ‌2nCr+1=‌2nC3r−1 ⇒(r+1)+(3r−1)=2n [As if ‌nCp=‌nCq then p+q=n ] ⇒4r=2n ⇒n=2r