Let the speed of the train be xkm∕hr. Relative Speed of Train and First Man: Relative speed =(x−6)km∕hr=(x−6)×5∕18m∕s Distance covered in crossing =(x−6)×5∕18×11 meters Relative Speed of Train and Second Man: Relative speed =(x−5)km∕hr=(x−5)×5∕18m∕s Distance covered in crossing =(x−5)×5∕18×10 meters Since the distance covered by the train in both cases is the same: (x−6)×11=(x−5)×10 Simplifying the equation: 11x−66=10x−50 11x−10x=66−50 x=16km∕hr