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NCERT Class XII Mathematics Chapter - - Solutions

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Question : 6 of 78
Marks: +1, -0
Exercise - 11.2
Show that the three lines with direction cosines 1213,313,413\frac{12}{13},-\frac{3}{13},-\frac{4}{13}; 413,1213,313\frac{4}{13},\frac{12}{13},\frac{3}{13}; 313,413,1213\frac{3}{13},-\frac{4}{13},\frac{12}{13} are mutually perpendicular.
Solution:  
Let the lines, whose direction cosines are given, be l1,l2l_1, l_2 and l3l_3 .
Let α be the angle between l1l_1 and l2l_2 , then
cosα=113413+(313)1213+(413)313\cos \alpha = \left| \frac{1}{13} \cdot \frac{4}{13} + \left(-\frac{3}{13}\right) \cdot \frac{12}{13} + \left(-\frac{4}{13}\right) \cdot \frac{3}{13} \right|
=483612169=0= \frac{48-36-12}{169}=0
α=π2l1l2\Rightarrow \alpha = \frac{\pi}{2} \Rightarrow l_1 \perp l_2
Similarly, we can show that l2l3l_2 \perp l_3 and l3l1.l_3 \perp l_1 .
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