Test Index

NCERT Class XII Mathematics Chapter - - Solutions

© examsnet.com
Question : 5 of 271
Marks: +1, -0
sin⁡2x−4e3x\sin 2x - 4 e^{3x}
Solution:  
Let I=∫(sin⁡2x−4e3x) dxI = \int (\sin 2x - 4 e^{3x}) \, dx
=−cos⁡2x2−4e3x3+C= - \frac{\cos 2x}{2} - \frac{4 e^{3x}}{3} + C
© examsnet.com
Go to Question:
Prev Question
Next Question
Advertisements