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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 47 of 271
Marks: +1, -0
1cos⁡2x(1−tan⁡x)2\frac{1}{\cos^2 x (1 - \tan x)^2}
Solution:  
Let I=∫1cos⁡2x(1−tan⁡x)2dxI = \int \frac{1}{\cos^2 x (1 - \tan x)^2} dx =∫sec⁡2x(1−tan⁡x)2dx= \int \frac{\sec^2 x}{(1 - \tan x)^2} dx
Put 1−tan⁡x=t1 - \tan x = t ⇒−sec⁡2x dx=dt\Rightarrow -\sec^2 x \, dx = dt
∴I=−∫dtt2\therefore I = -\int \frac{dt}{t^2} =−t−2+1−2+1+C= -\frac{t^{-2+1}}{-2+1} + C =11−tan⁡x+C= \frac{1}{1 - \tan x} + C
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