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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 46 of 271
Marks: +1, -0
2cos⁡x−3sin⁡x6cos⁡x+4sin⁡x\frac{2\cos x-3\sin x}{6\cos x+4\sin x}
Solution:  
Let I=∫2cos⁡x−3sin⁡x6cos⁡x+4sin⁡xdxI=\int \frac{2\cos x-3\sin x}{6\cos x+4\sin x}dx
12∫2cos⁡x−3sin⁡x2sin⁡x+3cos⁡x\frac{1}{2}\int \frac{2\cos x-3\sin x}{2\sin x+3\cos x}
Put 2sin⁡x+3cos⁡x=t2\sin x+3\cos x=t
⇒(2cos⁡x−3sin⁡x)dx=dt\Rightarrow (2\cos x-3\sin x)dx=dt
∴I=12∫dtt=12log⁡∣t∣+C\therefore I=\frac{1}{2}\int \frac{dt}{t}=\frac{1}{2}\log{|t|}+C
=12log⁡∣2sin⁡x+3cos⁡x∣+C=\frac{1}{2}\log{|2\sin x+3\cos x|}+C
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