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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 42 of 271
Marks: +1, -0
e2x−e−2xe2x+e−2x\frac{e^{2x}-e^{-2x}}{e^{2x}+e^{-2x}}
Solution:  
Let I=∫e2x−e−2xe2x+e−2xI=\int \frac{e^{2x}-e^{-2x}}{e^{2x}+e^{-2x}}
Put e2x+e−2x=te^{2x}+e^{-2x}=t
⇒(2e2x−2e−2x)dx=dt\Rightarrow (2e^{2x}-2e^{-2x})dx=dt
⇒(e2x−e−2x)dx=dt2\Rightarrow (e^{2x}-e^{-2x})dx=\frac{dt}{2}
∴I=12∫1tdt=12log⁡∣t∣+C\therefore I=\frac{1}{2}\int \frac{1}{t}dt = \frac{1}{2}\log|t|+C =12log⁡∣e2x+e−2x∣+C=\frac{1}{2}\log|e^{2x}+e^{-2x}|+C
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