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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 33 of 271
Marks: +1, -0
xx+4,x>0\frac{x}{\sqrt{x+4}}, x > 0
Solution:  
Let I=∫xx+4dxI=\int \frac{x}{\sqrt{x+4}} dx
Put x+4=tx + 4 = t ⇒dx=dt\Rightarrow dx = dt. Also x=t−4x = t - 4
∴I=∫t−4tdt\therefore I = \int \frac{t-4}{t} dt =∫(t1/2−4t−1/2)dt= \int (t^{1/2} - 4 t^{-1/2}) dt
=23t3/2−4×2t1/2+C= \frac{2}{3} t^{3/2} - 4 \times 2 t^{1/2} + C
=23(x+4)3/2−8(x+4)1/2+C= \frac{2}{3} (x+4)^{3/2} - 8 (x+4)^{1/2} + C
=23(x+4)1/2[x+4−12]+C= \frac{2}{3} (x+4)^{1/2} \left[ x+4-12 \right] + C
=23(x+4)1/2[x−8]+C= \frac{2}{3} (x+4)^{1/2} \left[ x-8 \right] + C
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