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NCERT Class XII Mathematics Chapter - - Solutions

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..... Miscellaneous Exercise .....
Integrate the functions in Exercises 229 to 252.
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Question : 245 of 271
Marks: +1, -0
f′(ax+b)[f(ax+b)]nf'(ax+b)[f(ax+b)]^n
Solution:  
Let I=∫f′(ax+b)[f(ax+b)]n dxI=\int f'(ax+b)[f(ax+b)]^n\,dx
Let f(ax+b)=tf(ax+b)=t ⇒af′(ax+b)dx=dt\Rightarrow af'(ax+b)dx=dt
∴I=1a∫tn dt=1a⋅tn+1n+1+C\therefore I=\frac{1}{a}\int t^n\,dt=\frac{1}{a}\cdot\frac{t^{n+1}}{n+1}+C
=1(n+1)a[f(ax+b)]n+1+C=\frac{1}{(n+1)a}[f(ax+b)]^{n+1}+C
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