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NCERT Class XII Mathematics Chapter - - Solutions

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Choose the correct answer in Exercises 196 and 197.
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Question : 197 of 271
Marks: +1, -0
∫02/3dx4+9x2\int\limits_{0}^{2/3}\frac{dx}{4+9x^2} equals
Solution:  
Let I=∫02/3dx4+9x2I=\int\limits_{0}^{2/3}\frac{dx}{4+9x^2} =19∫02/3dx(23)2+x2=\frac{1}{9}\int\limits_{0}^{2/3}\frac{dx}{\left(\frac{2}{3}\right)^2 + x^2}
=19×123[tan⁡−1(3x2)]02/3=\frac{1}{9}\times\frac{1}{\frac{2}{3}}\left[\tan^{-1}\left(\frac{3x}{2}\right)\right]_{0}^{2/3}
=16[tan⁡−1(3x2)]02/3=\frac{1}{6}\left[\tan^{-1}\left(\frac{3x}{2}\right)\right]_{0}^{2/3}
=16[tan⁡−11−tan⁡−10]=\frac{1}{6}\left[\tan^{-1}1-\tan^{-1}0\right]
=16×π4=π24=\frac{1}{6}\times\frac{\pi}{4}=\frac{\pi}{24}
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