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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.9
Evaluate the definite integrals in Exercises 176 to 195.
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Question : 176 of 271
Marks: +1, -0
∫−11(x+1)dx\int\limits_{-1}^{1}(x+1)dx
Solution:  
∫−11(x+1)dx\int\limits_{-1}^{1}(x+1)dx =[x22+x]−11=\left[\frac{x^2}{2}+x\right]_{-1}^{1}
=12[12−(−1)2]+[1−(−1)]=\frac{1}{2}[1^2-(-1)^2]+[1-(-1)]
=12(1−1)+(1+1)=\frac{1}{2}(1-1)+(1+1)
=12(0)+2=2=\frac{1}{2}(0)+2=2
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