Test Index

NCERT Class XII Chemistry
Chapter - Amines
Questions with Solutions

© examsnet.com
Question : 11 of 22
Marks: +1, -0
Complete the following reactions :
(i) C6H5NH2+CHCl3+alc.KOH→\mathrm{C}_6\mathrm{H}_5\mathrm{NH}_2 + \mathrm{CHCl}_3 + \mathrm{alc.KOH} \rightarrow
(ii) C6H5N2Cl+H3PO2+H2O→\mathrm{C}_6\mathrm{H}_5\mathrm{N}_2\mathrm{Cl} + \mathrm{H}_3\mathrm{PO}_2 + \mathrm{H}_2\mathrm{O} \rightarrow
(iii)C6H5NH2+H2SO4(conc.)→\mathrm{C}_6\mathrm{H}_5\mathrm{NH}_2 + \mathrm{H}_2\mathrm{SO}_4 (\text{conc.}) \rightarrow
(iv) C6H5N2Cl+C2H5OH→\mathrm{C}_6\mathrm{H}_5\mathrm{N}_2\mathrm{Cl} + \mathrm{C}_2\mathrm{H}_5\mathrm{OH} \rightarrow
(v) C6H5NH2+Br2(aq)→\mathrm{C}_6\mathrm{H}_5\mathrm{NH}_2 + \mathrm{Br}_2(\text{aq}) \rightarrow
(vi) C6H5NH2+(CH3CO)2O→\mathrm{C}_6\mathrm{H}_5\mathrm{NH}_2 + \mathrm{(CH_3CO)_2O} \rightarrow
(vii) →(ii) NaNO2/Cu, Δ(i) HBF4\xrightarrow[(ii)\,\mathrm{NaNO}_2/\mathrm{Cu},\,\Delta]{(i)\,\mathrm{HBF}_4}
Solution:  
(ii)C6H5N2ClBenzenediazonium chloride+H3PO2+H2O→ReductionCu+C6H6Benzene+N2+H3PO3+HCl(ii) \underset{\text{Benzenediazonium chloride}}{\mathrm{C}_6\mathrm{H}_5\mathrm{N}_2\mathrm{Cl}} + \mathrm{H}_3\mathrm{PO}_2 + \mathrm{H}_2\mathrm{O} \xrightarrow[\text{Reduction}]{\mathrm{Cu}^{+}} \underset{\text{Benzene}}{\mathrm{C}_6\mathrm{H}_6} + \mathrm{N}_2 + \mathrm{H}_3\mathrm{PO}_3 + \mathrm{HCl}
(iii)C6H5NH2Aniline+H2SO4(conc.)→C6H5N+H3HSO4−Anilinium hydrogen sulphate(iii) \underset{\text{Aniline}}{\mathrm{C}_6\mathrm{H}_5\mathrm{NH}_2} + \mathrm{H}_2\mathrm{SO}_4 (\text{conc.}) \rightarrow \underset{\text{Anilinium hydrogen sulphate}}{\mathrm{C}_6\mathrm{H}_5\overset{+}{\mathrm{N}}\mathrm{H}_3\mathrm{HSO}_4^{-}}
(iv)C6H5N2ClBenzenediazonium chloride+C2H5OH→ReductionC6H6Benzene+CH3CHOEthanal+N2+HCl(iv) \underset{\text{Benzenediazonium chloride}}{\mathrm{C}_6\mathrm{H}_5\mathrm{N}_2\mathrm{Cl}} + \mathrm{C}_2\mathrm{H}_5\mathrm{OH} \xrightarrow[\text{Reduction}]{} \underset{\text{Benzene}}{\mathrm{C}_6\mathrm{H}_6} + \underset{\text{Ethanal}}{\mathrm{CH}_3\mathrm{CHO}} + \mathrm{N}_2 + \mathrm{HCl}
© examsnet.com
Go to Question:
Prev Question
Next Question