Test Index

NCERT Class XII Chemistry
Chapter - Amines
Questions with Solutions

© examsnet.com
Question : 10 of 22
Marks: +1, -0
An aromatic compound ‘A’ on treatment with aqueous ammonia and heating forms compound ‘B’ which on heating with Br2\mathrm{Br}_2 and KOH forms a compound ‘C’ of molecular formula C6H7N\mathrm{C}_6\mathrm{H}_7\mathrm{N}. Write the structures and IUPAC names of compounds A, B and C.
Solution:  
Given scheme of reactions is
AAromatic compd.aq.NH3/ΔBBr2/KOHCC6H7N\underset{\text{Aromatic compd.}}{A}\xrightarrow{\mathrm{aq.NH}_3/\Delta}B\xrightarrow{\mathrm{Br}_2/\mathrm{KOH}}\underset{\mathrm{C}_6\mathrm{H}_7\mathrm{N}}{C}
(i) Looking at the given scheme, we can clearly see that reaction B → C is Hofmann bromamide reaction.
Thus, C is an amine (1°) while B must be an amide with molecular formula C7H7NO\mathrm{C}_7\mathrm{H}_7\mathrm{NO}.
(ii) Further, the ratio of C and H in B and C are indicativeof the fact that it is an aromatic compound.
Since, B is formed by the action of ammonia on A, A must be a carboxylic acid,
The reactions are
© examsnet.com
Go to Question: