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Mechanical Properties of Solids

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Question : 16 of 21
Marks: +1, -0
How much should the pressure on a litre of water be changed to compress it by 0.10%.
Solution:  
Here, V=1V=1 litre, ΔV=0.10%\Delta V=0.10\% of V=0.10100×1=11000V = \frac{0.10}{100} \times 1 = \frac{1}{1000} litre
Let ΔP\Delta P = Change in pressure required for compression of 1 litre of water.
B = bulk modulus of water =2.2×109Nm2= 2.2 \times 109 \, \mathrm{N} \, \mathrm{m}^{-2}
Using the relation, B=ΔP(ΔVV),B = \frac{\Delta P}{ \left( \frac{\Delta V}{V} \right) }, we get
ΔP=BΔVV\Delta P = B \frac{\Delta V}{V}
=2.2×109×110001= 2.2 \times 10^{9} \times \frac{ \frac{1}{1000} }{1}
=2.2×1091000= \frac{2.2 \times 10^{9}}{1000}
=2.2×106Nm2= 2.2 \times 10^{6} \, \mathrm{N} \, \mathrm{m}^{-2}
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