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NCERT Class XI Mathematics - Trigonometric Functions - Solutions

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Question : 16 of 61
Marks: +1, -0
sin (−11π3)\left(-\frac{11\pi}{3}\right)
Solution:  
sin (−11π3)\left(-\frac{11\pi}{3}\right) = - sin (11π3)\left(\frac{11\pi}{3}\right) [Since sin (– θ) = – sinθ]
= - sin (4π−π3)\left(4\pi - \frac{\pi}{3}\right) = sin (π3)\left(\frac{\pi}{3}\right) = 32\frac{\sqrt{3}}{2}
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