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NCERT Class XI Mathematics - Trigonometric Functions - Solutions

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Question : 15 of 61
Marks: +1, -0
tan 19π3\frac{19\pi}{3}
Solution:  
tan 19π3\frac{19\pi}{3} = tan (6π+π3)\left(6\pi + \frac{\pi}{3}\right) = tan π3\frac{\pi}{3} = 3\sqrt{3}
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